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x^2+6.67x-2.67=0
a = 1; b = 6.67; c = -2.67;
Δ = b2-4ac
Δ = 6.672-4·1·(-2.67)
Δ = 55.1689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.67)-\sqrt{55.1689}}{2*1}=\frac{-6.67-\sqrt{55.1689}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.67)+\sqrt{55.1689}}{2*1}=\frac{-6.67+\sqrt{55.1689}}{2} $
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